Dynamic number of where method in compound queries for firestore

Question

How to create the firestore query with a list of conditions:

function createQuery(conditions){
  // if conditions is = [
  //   ["state", "==", "CO"],
  //   ["name", "==", "Denver"]
  // ]
  return query; // will return query(citiesRef, where("state", "==", "CO"), where("name", "==", "Denver"));
}

Answer

See answer: Firestore conditional where clause using Modular SDK v9

let q = query(collection(firestore, "articles"))

// filters selected by users
if (status) q = query(q, where("status", "==", "live"))
if (publishedAfter) q = query(q, where("publishedAt", ">", publishedAfter))

---

From the documentation on compound queries, to have multiple conditions in query, we can do this:

const q1 = query(citiesRef, where("state", "==", "CO"), where("name", "==", "Denver"));

And if I have 3 conditions, we can do this:

const q1 = query(citiesRef, where("state", "==", "CO"), where("name", "==", "Denver"), where("age", "==", 30));

How can we dynamically add where into query such that given:

let conditions = [
  ["state", "==", "CO"],
  ["name", "==", "Denver"]
]

will return:

const q1 = query(citiesRef, where("state", "==", "CO"), where("name", "==", "Denver"));

And

let conditions = [
  ["state", "==", "CO"],
  ["name", "==", "Denver"],
  ["age", "==", 30]
]

will return:

const q1 = query(citiesRef, where("state", "==", "CO"), where("name", "==", "Denver"), where("age", "==", 30));