Display all resoult if text not cointaint strings from the list

Question

Look ath this example

if ('.NET' or 'JS' or 'python' or 'Java') not in title:
    print(title)

It's a part of my code. Title is a string. I want to display title only if not contain any one element of the list. In this example it only exculdes .NET. How can I solve my problem?

What is the value of `('.NET' or 'JS' or 'python' or 'Java')`? — Scott Hunter, Jan 05 '22 at 20:44
If you try to run `'.NET' or 'JS' or 'python' or 'Java'` you will get `'.NET'` — Riccardo Bucco, Jan 05 '22 at 20:44
I want that if only one element with this list will contain in title, it shouldn;t be print. — wtsuport, Jan 05 '22 at 20:46
See https://www.geeksforgeeks.org/python-test-if-string-contains-element-from-list/ — PM 77-1, Jan 05 '22 at 20:53

Riccardo Bucco · Answer 1 · 2022-01-05T20:52:41.317

0

You need to rewrite your statement in this way:

if ('.NET' not in title and
    'JS' not in title and
    'python' not in title and
    'Java' not in title):

Or:

if all(x not in title for x in ('.NET', 'JS', 'python', 'Java')):

edited Jan 05 '22 at 20:52

answered Jan 05 '22 at 20:50

Riccardo Bucco

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`('.NET' or 'JS' or 'python' or 'Java')` still resolves to just `'.NET'`. Use `for x in ['.NET', 'JS', 'python', 'Java']` instead. – John Gordon Jan 05 '22 at 20:51
@JohnGordon Yes, sorry, I just copied and pasted the code from the question haha – Riccardo Bucco Jan 05 '22 at 20:53

Display all resoult if text not cointaint strings from the list

1 Answers1