PHP implode and explode functions

Question

I have this sentence:

piece:5,dozen:10

and I need to print it via php like this:

piece:5$,dozen:10$

without editing the line in the editor, I need php to do it automatically. Now I thought to split it like this:

$uom = "piece:5,dozen:10";
$lst1 = explode(',', $uom);
var_dump($lst1);

and it returned like this:

array (size=2)

0 => string 'piece:5' (length=7)

1 => string 'dozen:10' (length=8)

which is ok for now, so I need after each string piece:5$ dozen:10$ and then I did this:

$lst2 = implode('$ ', $lst1);
echo $lst2;

It printed:

piece:5$ dozen:10

I need the $ to be printed also after 10, so it will be like this:

piece:5$ dozen:10$

What is the right way to do this? What did I do wrong? What if the values are dynamically coming from the database?

you can use string implode('$ ', $lst1) . (count($lst1) > 0 ? "$" : "") ... implode join items by char but not add char at the end because end is not join another item :) — daremachine, Dec 28 '21 at 23:32
Am I misunderstanding something here? Why not just `$lst2 = implode('$ ', $lst1) . '$';` — miken32, Dec 29 '21 at 00:00
@daremachine Thanks! It worked! Does this works too if the values are coming dynamically from the database? — DBblack, Dec 29 '21 at 00:21
@miken32 Thanks! It worked! Does this works too if the values are coming dynamically from the database? — DBblack, Dec 29 '21 at 00:24
@miken32 if lst1 is empty then you get $ char. This is bad. You should get empty string instead. — daremachine, Dec 29 '21 at 01:19
@daremachine that’s a trivial thing to check for, and the duplicate target contains many more robust solutions. — miken32, Dec 29 '21 at 01:42
@DBblack my approach return empty string if array is empty. .'$' will be always. No matter if array is empty or not. Try both and you see. — daremachine, Dec 29 '21 at 01:48
@daremachine How can I do the exact same thing using JQuery? — DBblack, Dec 29 '21 at 03:18

score 0 · Answer 1 · answered Dec 28 '21 at 23:42

0

You can use a combination of explode, array_map and implode like so:

<?php

$uom = 'piece:5,dozen:10';

$add_dollars = array_map(function($e) {
    return $e . '$';
}, explode(',', $uom));

echo implode(" ", $add_dollars);

answered Dec 28 '21 at 23:42

Jacob Mulquin

2,486
1
17
22

Thanks! It worked! Does this works too if the values are coming dynamically from the database? – DBblack Dec 29 '21 at 00:28
How can I do the exact same thing using JQuery? – DBblack Dec 29 '21 at 03:19
@DBblack you're looking for the `split` method (explode), `map` (array_map) and `join` (impode) – Jacob Mulquin Dec 29 '21 at 05:01

Sylogista · Answer 2 · 2021-12-29T04:22:21.443

0

I see few explode-implode answers. I don't want to duplicate answer, so let me do it another way – with regex.

$data = "piece:5,dozen:10";
echo preg_replace("/(\d+)/i", "$1\$", $data);

It may be a good idea to make it a bit more complex, i.e. take not only \d+, but also previous string and colon. Rather without(!) comma. In my opinion this may be better (because it's usually worth to be strict in regex):

$data = "piece:5,dozen:10";
echo preg_replace("/([a-zA-Z]:\d+)/i", "$1\$", $data);

I encourage you to read php manual: preg_replace.

Answering also the question about jQuery – you don't need to use jQuery, you can do that in pure javascript. And it will be really similar! For example:

let data = "piece:5,dozen:10";
let modified = data.replace(/([a-zAZ]:\d+)/g,"$1\$");
console.log(modified);

edited Dec 29 '21 at 04:22

answered Dec 29 '21 at 00:13

Sylogista

480
3
9

How can I do the exact same thing using JQuery? – DBblack Dec 29 '21 at 03:19
@DBblack you don't need jQuery, it's possible in pure javascript. I'm going to add that to my main answer. – Sylogista Dec 29 '21 at 04:17
@DBblack you need learn javascript Regular_Expressions and use what Sylogista wrote. – daremachine Dec 29 '21 at 04:38

PHP implode and explode functions

2 Answers2