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Please Help, I will display the link in json, but an error appears

when img*=link

$img1 = "$row['img1']";
$img2 = "$row['img2']" ;
$img3 = "$row['img3']" ;
$json .= ',"img1" : "'."<a href='".$row['img1']."'><span>".$img1."</span></a>".'"';
$json .= ',"img3" : "'."<a href='".$row['img3']."'><span>".$img2."</span></a>".'"';
$json .= ',"img2" : "'."<a href='".$row['img2']."'><span>".$img3."</span></a>".'"';

unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING)

Eat Gaboon
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0 Answers0