std::unique_ptr(new int); vs std::make_unique();

Asked Dec 27 '21 at 18:39

Active Dec 27 '21 at 18:39

Viewed 20 times

Is there any reason to choose

int pInt = std::unique_ptr<int>(new int);

int pInt = std::make_unique<int>()

other than avoiding specifying the type twice?

asked Dec 27 '21 at 18:39

ROBERT RICHARDSON

Multiple reasons have been mentioned in [Differences between std::make_unique and std::unique_ptr with new](https://stackoverflow.com/q/22571202/555045) and [Advantages of using std::make_unique over new operator](https://stackoverflow.com/q/37514509/555045) – harold Dec 27 '21 at 18:43

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