Lambda expression to normal function

Question

I am trying to understand lambda Python code. How to translate this in normal Python?

self.myarray = [j for j in line if j.type not in (obj.key1, obj.key2)]

it's not lambda, btw, it's a list comprehension. you can replicate with a normal `for` loop. are you familiar with those? — mechanical_meat, Dec 22 '21 at 15:29
See: https://docs.python.org/3/tutorial/datastructures.html#list-comprehensions — Christian Dean, Dec 22 '21 at 15:40
It is normal Python. I assume you mean with a `for` loop and not a list comprehension? — chepner, Dec 22 '21 at 19:53
BTW, welcome to Stack Overflow! Check out the [tour] and [ask]. — wjandrea, Dec 22 '21 at 19:55

score 1 · Answer 1 · edited Dec 22 '21 at 19:52

1

That syntax represents a list comprehension and it does the same thing as below code:

self.myarray = []
for j in line:
    if j.type not in (obj.key1, obj.key2):
        self.myarray.append(j)

edited Dec 22 '21 at 19:52

Chris

answered Dec 22 '21 at 19:31

1 Answers1