Sort with compare() first alphabeticlly and then by lenght

Question

Hi how can I use compare to first sort an array alphabetically and then according to length. (longer words before short words) e.g. first appletree, apple, baron.

@Override
public int compare(Term o1, Term o2) {
    // TODO Auto-generated method stub
    if (o1.getTerm().compareTo(o2.getTerm()) < 1 && o1.getTerm().length() > o2.getTerm().length()) {
        return -1;
    }

    else
        return 0;

}

With the example above I get the words alphabetically but not lengthwise