using "grep" to print the lines where the same sequence of 4 or more consecutive characters comes in at least 3 times

Question

I'm trying to find the lines where the same sequence of 4 or more consecutive characters comes in at least 3 times, using the grep command

 grep '^.*\(....\)*\1*\1*' file.name

for ex

  ADShDS DFDFG HGFDFDFD DFDFD
  ASFG VVFGTTTE DSrFD GFFDSD C
  KKKYX KKKYXFF KaKFVBB KKKYXY

expected output

  ADShDS DFDFG HGFDFDFD DFDFD
  KKKYX KKKYXFF KaKFVBB KKKYXY

but there is something wrong !?

Cyrus · Accepted Answer · 2021-10-22T23:59:45.230

1

I suggest:

grep '\(....\).*\1.*\1' file

or

grep -E '(....).*\1.*\1' file

edited Oct 22 '21 at 23:59

answered Oct 22 '21 at 23:15

Cyrus

i meant where the same sequence of 4 or more consecutive characters ( only big letters ) comes in at least 3 times – DOS HASAN Oct 22 '21 at 23:25
grep '\([A-Z][A-Z][A-Z][A-Z]\).*\1.*\1' , this work – DOS HASAN Oct 22 '21 at 23:28

1 Answers1