Is there a way to run a function using variable name?

Question

I've created a python code that automatically join zoom classes at a specific time using the schedule module. This is an example code below:

schedule.every().monday.do(join_zoom)

Is there a way that i can run the code like this

date = "monday"
schedule.every().[date].do(join_zoom)

Thanks

@Random_Pythoneer59 doesn't work – SuperStormer Oct 13 '21 at 17:34 — SuperStormer, Oct 13 '21 at 17:34

score 0 · Answer 1 · answered Oct 13 '21 at 17:29

0

Sure, a simple if-else statement will do:

date = "monday"

if date == "monday":
    schedule.every().monday.do(join_zoom)
elif date == "tuesday":
    schedule.every().tuesday.do(join_zoom)

etc.

answered Oct 13 '21 at 17:29

RJ Adriaansen

7,587
2
8
22

score 0 · Accepted Answer · answered Oct 13 '21 at 17:38

0

Sure, getattr is what you're looking for:

date = "monday"
getattr(schedule.every(), date).do(join_zoom)

If you want, you can try it out with this self-built snippet:

class Schedule:

    @staticmethod
    def every():
        return Day

class FooBar:

    @staticmethod
    def do(stringg):
        print('success')

class Day:
    monday = FooBar
    tuesday = FooBar


schedule = Schedule
getattr(schedule.every(), 'monday').do('ciao')

answered Oct 13 '21 at 17:38

scandav

690
7
19

Please don't repeat answers that are already present on the duplicate I linked. – SuperStormer Oct 13 '21 at 17:49
I didn't see the duplicate as we posted at the same time – scandav Oct 13 '21 at 17:50

Is there a way to run a function using variable name?

2 Answers2