#include<stdio.h>
int main(){
int i=30;
int *ptr=&i;
printf("Value of i is %d\n",*ptr);
ptr++;
printf("Value of i is %d\n",*ptr);
return 0;
}
//OUTPUT:-
Value of i is 30
Value of i is 6618648
Asked
Active
Viewed 26 times
0
dbush
- 186,650
- 20
- 189
- 240
-
How do you know it is the address of the integer? Anyway, the code is invalid because the result of incrementing and accessing a pointer beyond the bounds of the variable it points to is undefined behaviour. – kaylum Oct 10 '21 at 21:41
-
read the dupes. Consider `i` as a single element integer array. – 0___________ Oct 10 '21 at 21:44
-
It is `(*ptr)++`, not what you wrote. – FaranAiki Oct 11 '21 at 02:38