How to extract part of string in Bash using regex

Question

I have been trying to extract part of string in bash. I'm using it on Mac.

Pattern of input string:

• Some random word follow by a /. This is optional.
• Keyword (def, foo, and bar) followed by hyphen(-) followed by numbers. This can be 2-6 digit numbers
• These numbers are followed by hyphens again and few hyphen separated words.

Sample inputs and outputs:

abc/def-1234-random-words // def-1234
bla/foo-12-random-words // foo-12
bar-12345-random-words // bar-12345

So I tried following command to fetch it but for some weird reason, it returns entire string.

extractedValue=`getInputString | sed -e 's/.*\(\(def\|bar\|foo\)-[^-]*\).*/\1/g'`
// and
extractedValue=`getInputString | sed -e 's/.*\(\(def\|bar\|foo\)-\d{2,6}\).*/\1/g'`

I also tried to make it case-insensitive using I flag but it threw error for me:

: bad flag in substitute command: 'I'

---

Following are the references I tried:

• Extract substring using regexp in plain bash
• Extract string from string using RegEx in the Terminal

Answer 1

This gnu sed should work with ignore case flag:

sed -E 's~^(.*/){0,1}((def|foo|bar)-[0-9]{2,6})-.*~\2~I' file

def-1234
foo-12
bar-12345

This sed matches:

• (.*/){0,1}: Match a string upto / optionally at the start
• (: Start capture group #2
  • (def|foo|bar): Match def or foo or bar
  • -: Match a -
  • [0-9]{2,6}: Match 2 to 6 digits
• ): End capture group #2
• -.*: Match - followed by anything till end
• Substitution is value we capture in group #2

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Or you may use this awk:

awk -v IGNORECASE=1 -F / 'match($NF, /^(def|foo|bar)-[0-9]{2,6}-/) {print substr($NF, 1, RLENGTH-1)}' file

def-1234
foo-12
bar-12345

Awk explanation:

• -v IGNORECASE=1: Enable ignore case matching
• -F /: Use / as field separator
• match($NF, /^(def|foo|bar)-[0-9]{2,6}-/): Match text using regex ^(def|foo|bar)-[0-9]{2,6}- in $NF which is last field using / as field separator (to ignore text before /)
• If match is successful then using substr print text from position 1 to RLENGTH-1 (since we matching until - after digits)

Answer 2

You can use the -E option to use extended regular expressions, then you don't have to escape ( and |.

echo abc/def-1234-random-words  | sed -E -e 's/.*((def|bar|foo)-[^-]*).*/\1/g'
def-1234