Get input for Y/n, get 'n' without enter?

Question

This is so common that I thought I could easily find existing code, but all the search results were not what I want. What I want is:

• Pressing 'Y' or 'y' (no enter) becomes YES.
• Pressing enter becomes YES, because YES is the default.
• Pressing 'N' or 'n' (no enter) becomes NO.
• All other keypresses are ignored.

The following code only works if I press enter after typing 'y' or 'n'. How can I get the value immediately as the user presses 'y'?

using namespace std;
int main()
{
    cout << "Do it? (Y/n): ";
    while (true)
    {
        auto input = cin.get();
        if (input == '\n' || input == 'y')
        {
            cout << "YES";
            break;
        }
        else if (input == 'n')
        {
            cout << "NO";
            break;
        }
    }
    cout << "Done.";
    cin.get();
}