Capture group in specific string

Question

I have a string:

User{self=https:example.com, name=S1234, displayName=Johny B, accountId=null, emailAddress=johny.b@example.com, active=true}'

I try to capture group and get Johny B in sed. I have proper regex: displayName=(.*?),

but below sed command return me all string:

's/.*displayName=\(.*?\),/\1/'

Does this answer your question? [Non greedy (reluctant) regex matching in sed?](https://stackoverflow.com/questions/1103149/non-greedy-reluctant-regex-matching-in-sed) — Wiktor Stribiżew, Sep 03 '21 at 09:13
ok, when I change to ```'s/.*displayName=\([^/]*\),/\1/'``` I get substring starting of```Johny B``` to the end of string — Kucharsky, Sep 03 '21 at 09:25
You have a comma to exclude, `'s/.*displayName=\([^,]*\),/\1/'`, not a slash. — Wiktor Stribiżew, Sep 03 '21 at 09:28

score 1 · Accepted Answer · answered Sep 03 '21 at 09:31

1

You can try this sed

sed -E 's/.*displayName=([^,]*).*/\1/' $file

You have further strings after the match which you need to account for.

answered Sep 03 '21 at 09:31

HatLess

1 Answers1