Can not solve problem i have following list ['882','200','60'] sometimes it can be ['882','200'] i want get list like this [['8','8','2'], '200', '60'].
Another words no matter how many items are in the list, we always split the first item
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2 Answers
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You can use enumerate to get the first element:
l = ['882','200','60']
[e if i else list(e) for i,e in enumerate(l)]
output:
[['8', '8', '2'], '200', '60']
other examples
>>> [e if i else list(e) for i,e in enumerate(['123'])]
[['1', '2', '3']]
>>> [e if i else list(e) for i,e in enumerate(['882','200'])]
[['8', '8', '2'], '200']
mozway
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mylist = ['882','200','60']
mylist[0] = list(mylist[0])
Bendik Knapstad
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1nice one, simple and efficient ;) +1 – mozway Aug 16 '21 at 11:34