what does this list() function do in the following line of code

Question

class Graph:
    def __init__(self, gdict=None):
        if gdict is None:
            gdict = {}
        self.gdict = gdict

    def bfs(self, start, end):
        queue = []
        queue.append([start])
        print('queue',queue)
        while queue:
            path = queue.pop(0)
            node = path[-1]
            print('path',path)
            if node == end:
                return path
            for adjacent in self.gdict.get(node, []):
                print('path in for loop',path)
                new_path = list(path)
                print('newpath',new_path)
                new_path.append(adjacent)
                queue.append(new_path)
                print('queue in for loop',queue)

customDict = { "a" : ["b", "c"],
               "b" : ["d", "g"],
               "c" : ["d", "e"],
               "d" : ["f"],
               "e" : ["f"],
               "g" : ["f"]
               }

g = Graph(customDict)
print(g.bfs("a", "g"))

this is a code for Single Source shortest path in graph using BFS my doubt is in for loop when new_path = list(path) is used i get a different answer new_path = path i get a differnt answer what does this list() do when i use without the list function the path is modified why....I have many print statements for debugging and for my understanding so please ignore