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If I run the curl with json directly as part of the syntax the request goes through but if I replace it with a variable it through error. How do I get around it

dataset='{
   "channel": "#staging2-setup",
   "username": "SQS Notification",
   "text": "test"
  }'

echo $dataset
curl -X POST \
https://slack.com/api/chat.postMessage \
-H 'authorization: Bearer xoxb-XXXXXXXXX' \
-H 'content-type: application/json' \
-d $dataset

Error message

{"ok":false,"error":"invalid_json","warning":"missing_charset","response_metadata":{"warnings":["missing_charset"]}}curl: (6) Could not resolve host: "channel"
curl: (6) Could not resolve host: "
curl: (6) Could not resolve host: "username"
curl: (6) Could not resolve host: "SQS
curl: (6) Could not resolve host: Notification",
curl: (6) Could not resolve host: "text"
curl: (6) Could not resolve host: "test"
curl: (3) [globbing] unmatched close brace/bracket in column 1
kumar
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0 Answers0