Can you tell why this statement in C gives 0 as output
printf("Hello %f",-5/2);
Whereas
printf("Hello %d",-5/2);
is giving output as -2
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2What is the type of output when two integers are divided? – DeBARtha Aug 02 '21 at 11:53
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2This here: `printf("Hello %f",-5/2);` causes UB. Read the specifications of `printf()` in the C standard or read the man page of `printf()`. – 12431234123412341234123 Aug 02 '21 at 11:54
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Division of two integers produces a integer result (int in this case). The %f format specifier expects an argument of type double. Using the wrong format specifier for a given argument triggers undefined behavior which in this case gives you an incorrect result.
If you want a floating point result, at least one of the operands to / must have a floating point type, i.e.
printf("Hello %f",-5.0/2);
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