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Here is my code :

#include<stdio.h>
int main()
{
    int a[10],b[10],i,j;

    printf("Enter the 10 element of array:\n");
    for(int i=0;i<10;i++)
    {
        scanf(" %d\n",&a[i]);
    }



    printf("The Original elements of array:\n");
    for(int i=0;i<10;i++)
    {
        printf(" %d\n",a[i]);
    }

    for(i=0,j=10;i<10;i++,j--)
    {
        b[i] = a[j-1];
    }

    printf("The revese order of  elements of array:\n");
    for(int i=0;i<10;i++)
    {
        printf(" %d\n",b[i]);
    }

    return 0;
}

out-put is: Enter the 10 element of array: 1 2 3 4 5 6 7 8 9 10 11

As,you can it get terminated once i enter 11,but i want it to terminate after 10.

The Original elements of array: 1 2 3 4 5 6 7 8 9 10

And here 11 is not showing up why?

The revese order of elements of array: 10 9 8 7 6 5 4 3 2 1 same here 11 is not showing up.

please check my code and help me out. thank you.

piyush kumar singh
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    Because `scanf(" %d\n",&a[i]);` has to match all the trailing whitespace, and doesn't know when it ends until non-whitespace is entered. Please use `scanf("%d",&a[i]);` The `scanf` function seems to resemble `printf` but is quite different. Every character placed in the format string is significant. – Weather Vane Jul 29 '21 at 07:04

0 Answers0