Why is the Output first, third and second??
console.log("first");
setTimeout(() => {
console.log('second');
}, 0);
console.log('third');
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Mister Jojo
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lordrayuga9
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1because `second` is coming from an async process – Mister Jojo Jul 25 '21 at 17:28
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1to add @MisterJojo, you can see [this video](https://youtu.be/8aGhZQkoFbQ?t=770) it explains the javascript event loop and everything related to it. – Syakhisk Al-azmi Jul 25 '21 at 17:30
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1Because `setTimeout` callback is put in a queue. Queued jobs will only execute when the current script has finished executing, and the call stack is empty. – trincot Jul 25 '21 at 17:34
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Thank You folks – lordrayuga9 Jul 25 '21 at 18:19