Python: str.lstrip removes more than the string supplied in the argument

Question

I've been trying to wrap my head around this problem for a couple hours now and cant figure out why this weird issue happens.

When using project as the value for lstrip it works as intended but if I use project_ as the value it removes the value project_c from the string channel.

This has only happened for me with this uuid and not any others so far.

channel = 'project_cae22ac4-ac76-47e7-977e-908e117f6475'

normal_result = channel.lstrip('project')   # '_cae22ac4-ac76-47e7-977e-908e117f6475'
weird_result  = channel.lstrip('project_')  #   'ae22ac4-ac76-47e7-977e-908e117f6475'

normal_result gets set to _cae22ac4-ac76-47e7-977e-908e117f6475 which is expected.

But when I add an underscore to remove the project along with the underscore it also removes the first letter 'c' from the uuid ae22ac4-ac76-47e7-977e-908e117f6475

Don't let the title of the duplicate fool you: "end of string" and "start of string" are the same tooling, just replace `rstrip` with `lstrip` and `endswith` with `startswith`. — Andras Deak -- Слава Україні, Jul 08 '21 at 00:33

Python: str.lstrip removes more than the string supplied in the argument

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