Structure variable initialization in short way

Question

Trying to initialize structure variable fields with values in short way:

typedef struct
{
    int id = 0;
    char* name = "none";
}employee;

employee e = 
{
    .id = 0 ;
    .name = "none" ;
};

Got error in e initialization:

Error    expected ‘}’ before ‘;’ token                                                  
Note     to match this ‘{’                                                              
Error    could not convert ‘{0}’ from ‘<brace-enclosed initializer list>’ to ‘employee’

Why I'm getting error and how to solve this problem?

Vlad from Moscow · Accepted Answer · 2021-06-20T14:09:43.673

0

In C you may not initialize data members in a structure definition. So you have to write

typedef struct
{
    int id;
    char* name;
}employee;

Also the separator in the list initialization is comma.

employee e = 
{
    .id = 0,
    .name = "none",
};

or

employee e = 
{
    .id = 0,
    .name = "none"
};

edited Jun 20 '21 at 14:09

answered Jun 20 '21 at 13:45

Vlad from Moscow

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Maybe you should just add that he can set inital value during the definition of a variable of that class – Dusan Todorovic Jun 20 '21 at 13:47
@DusanTodorovic it is C. No classes. – 0___________ Jun 20 '21 at 13:51
Compiler is happy regarding typedef struct `{ int id = 0; char* name = "none"; }employee;` But responds with error `could not convert ‘{0, "none"}’ from ‘’ to ‘employee’` to `employee e = { .id = 0, .name = "none" };` – vico Jun 20 '21 at 14:02
2

@vico It means that you are compiling the program as a C++ program. – Vlad from Moscow Jun 20 '21 at 14:04
@0___________ i wanted to type struct. Typo – Dusan Todorovic Jun 20 '21 at 14:17

Structure variable initialization in short way

1 Answers1