How to implement else for display simple text echo php

Question

I'm getting an error in my code and I wanted to implement an else just so that the error was not displayed, but a text stating that the user needs to be logged in for this action. someone could help me, I appreciate it and all help is welcome.

error: Erro: Undefined index: usuario_id no arquivo C:\xampp\htdocs\framework\app\Views\posts\ver.php na linha 39

My code.

            <div class="col-md-6">
                 <?php if ($dados['post']->usuario_id == $_SESSION['usuario_id']) : ?>
                 
        <ul class="list-inline">
            <li class="list-inline-item">
                <a href="<?= URL . '/dashboard/editar/post/' . $dados['post']->id ?>" class="btn btn-sm btn-primary" data-toggle="tooltip" title="Editar o Post  <?= $dados['post']->titulo ?>">Editar</a>
            </li>
            <li class="list-inline-item">
                <form action="<?= URL . '/posts/deletar/' . $dados['post']->id ?>" method="POST">
                    <input type="submit" class="btn btn-sm btn-danger" value="Deletar" data-toggle="tooltip" title="Deletar o Post  <?= $dados['post']->titulo ?>">
                </form>
            </li>
            
        </ul>
        

    <?php endif ?>
            
                
            </div>

LINE39.

<?php if ($dados['post']->usuario_id == $_SESSION['usuario_id']) : ?>

use isset, its undefined index, so its not set – Lawrence Cherone Jun 12 '21 at 18:29 — Lawrence Cherone, Jun 12 '21 at 18:29

How to implement else for display simple text echo php

0 Answers0