I'm declaring an object literal like
object = { a: func1(), b: func2() }
func1 has to be executed before func2.
Are func1 and func2 guaranteed to be executed in the order they're called in the object declaration?
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T.J. Crowder
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LOL, just came back to mark that same duplicate, having found it. – T.J. Crowder May 31 '21 at 13:47
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Short answer: Yes, it's guaranteed. The property initializers are executed in source code order. – T.J. Crowder May 31 '21 at 13:47