Regex find url with specefic character inside (js)

Question

I have the following text:

Some text
{\"url\": \"https:\/\/www.someurl.com\/200x200\/fsdffsde3e", \"bbb\"} kljkl
{\"url\": \"https:\/\/www.someurl.com\/500x500\/fsdffsde3e", \"bbb\"} kljkl
Some text

I want to extract all the URLs contains 200x200. so for example I need this URL: https:\/\/www.someurl.com\/200x200\/fsdffsde3e

this, will bring the entire row: "https(.*?)200x200(.*)" but I want only the URL. Have a look: https://regex101.com/r/DDWLDM/1

Thanks

Use `.*?` everywhere, or `[^"]*` (see [here](https://stackoverflow.com/a/14997763/3832970)). — Wiktor Stribiżew, May 26 '21 at 12:38

score 0 · Answer 1 · answered May 26 '21 at 12:43

0

use This exp

"https(.*?)200x200(.*?)"

answered May 26 '21 at 12:43

Shantanu Sharma

551
5
19

Brings only part of the url – SexyMF May 26 '21 at 13:24

Regex find url with specefic character inside (js)

1 Answers1