PHP intval() weird result on basic calculation

Question

Hello,

$expression="1*2";
var_dump(intval($expression));

gives int 1

why ?

Thanks for helping

Does this answer your question? [PHP: Understanding string type juggling](https://stackoverflow.com/questions/34044348/php-understanding-string-type-juggling) — emix, May 15 '21 at 18:09
no emix i wanted to evaluate it, but it's recognized as a mathematic expression, and i'd like it to be — BrainUnderflow, May 15 '21 at 19:24
I found something here : [https://stackoverflow.com/questions/18880772/calculate-math-expression-from-a-string-using-eval](https://stackoverflow.com/questions/18880772/calculate-math-expression-from-a-string-using-eval) — BrainUnderflow, May 15 '21 at 19:39

score 2 · Answer 1 · answered May 15 '21 at 16:08

2

There is using common type cast rules. In string "1*2" second char is not numeric. Takes only left side. https://www.php.net/manual/en/language.types.integer.php#111523

answered May 15 '21 at 16:08

Nikita Ivanov

score 1 · Answer 2 · answered May 15 '21 at 18:18

1

If you are wanting the expression to be evaluated as an expression, use the eval() function.

But this is not recommended unless you filter $expression for dangerous characters.

answered May 15 '21 at 18:18

Phil Y

2 Answers2