console.log(Number.parseFloat('123456789021.123457'));Output: 123456789021.12346
Expected output: 123456789021.123457
Why does the Number.parseFloat function automatically round the last digit?
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connexo
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Ajay Ullal
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what output are you expecting from that number string? – crispengari Apr 09 '21 at 15:53
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1Short answer: Because it has too many digits. Long answer see: linked duplicate – derpirscher Apr 09 '21 at 15:55
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Specifically look at T.J. Crowder's answer on the linked dup. – Teemu Apr 09 '21 at 15:58
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What about [toFixed()](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Number/toFixed) ? – dominagy Apr 09 '21 at 16:50