How to parse an 8 digit number as a date?

Question

I need to build a way to automate file names, and I was curious as to if there is a function or a quick way to take in 8 digits and output the corresponding Date.

Specifically I only need the Month and year.

Example: 03232021 -> Mar2021

I was trying pandas to_datetime but it didn't seem like it was what I needed.

Duplicates have different order of the `strptime` format codes, but it's a trivial translation. — ShadowRanger, Mar 31 '21 at 14:31

score 3 · Accepted Answer · answered Mar 31 '21 at 14:26

In [133]: s = "03232021"                                                                                                                                                                                                                                                      

In [134]: dt.datetime.strptime(s, "%m%d%Y").date()                                                                                                                                                                                                                            
Out[134]: datetime.date(2021, 3, 23)

How to parse an 8 digit number as a date?

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