Trying to get user input (asking for an integer) and making it loop until the user inputs an integer. Trying to use While true, try and except

Question

tries = 0
while True:
    try:
      imput = int(input("Input An Integer: "))
      if imput != 0:
      print(imput)
    except ZeroDivisionError:
        print("Bro what you doin?")
    except TypeError:
        print("Bruh What you doin?")

score 0 · Answer 1 · edited Mar 22 '21 at 15:07

0

This should work:

With a boolean you can safe, whether an integer was given or not

got_int = False

As long as no integer was given, it waits for the next input

while got_int == False:

    try:
        user_input = int(input('Input an integer: '))
        got_int = True
    except:
        print("That's not an integer")

It seems to me that you are not so familiar with try except. If so, you can read more about it here

edited Mar 22 '21 at 15:07

Tomerikoo

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answered Mar 22 '21 at 14:59

Max Müller

66
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1

A more idiomatic, pythonic way to write such loop is using `while True:` and `break`ing once the condition is satisfied instead of using a "flag" variable – Tomerikoo Mar 22 '21 at 15:08

Trying to get user input (asking for an integer) and making it loop until the user inputs an integer. Trying to use While true, try and except

1 Answers1