R: use strsplit transform to list that is not length of 1

Asked Mar 15 '21 at 08:43

Active Mar 15 '21 at 08:43

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I was writing some code that need to inspect individual characters in a input string. I want to know whether there were numbers in string, and use strsplit to split the character into list. Then, use any() to check the numbers (the limitation is that I can't use grepl :(

b<-"Idontknow456"
b<-strsplit(b,"")
length(b)
any(6%in%b)

c<-list("d","t","5")
length(c)
any(5%in%c)

the result

  1
  FALSE
  3
  TRUE

May I ask how should I modify my code, so that I can split individual characters to inspect them?

asked Mar 15 '21 at 08:43

Ping Jung

You may need `unlist` or `[[1]]` to get a vector back i.e `b – Ronak Shah Mar 15 '21 at 08:46
strsplit returns list, try `any("6" %in% unlist(b))` – zx8754 Mar 15 '21 at 08:46
But the solution is regex, see: https://stackoverflow.com/q/33393112/680068 – zx8754 Mar 15 '21 at 08:48
Maybe you can also try: `utf8ToInt("6") %in% utf8ToInt(b)` – GKi Mar 15 '21 at 09:12

R: use strsplit transform to list that is not length of 1

0 Answers0