Get path for the file being run and not the dir of where the call is from

Question

Say I have the following /home/my_user/files/path.py which contains print(os.getcwd()) and I from /home/ run

python3 ./my_user/files/path.py

I get the output /home/. Is there a way to print the folder of which the file being run is e.g /home/my_user/files independantly of where the file is run from?

Answer 1

This will give you the absolute path of the directory of the executed python file

os.path.dirname(os.path.abspath(__file__))

Answer 2

You want the directory of the Python file, not the working directory:

import os.path

print(os.path.dirname(__file__))

Answer 3

You need to get the file's realpath, not the current directory

import os

os.path.dirname(os.path.realpath(__file__))