Equivalent to ti = 1:step:len of Matlab in Python

Question

What is the equivalent of the following MATLAB code that generates a time vector in Python?

ti = 1:step:len

[This question](/questions/477486/how-to-use-a-decimal-range-step-value) is not an exact dupe but it answers your question: — Pranav Hosangadi, Feb 02 '21 at 15:24

score 1 · Accepted Answer · edited Feb 02 '21 at 15:28

1

use numpy.arange:

import numpy as np

# ti = np.arange(start, end, step)
ti = np.arange(1,last+step,step)

If you want to go from 1 to 10 with 0.5 as the step (including 1 and 10), you would write it as:

ti = np.arange(1,10.5,0.5)

If you used 10 as the end argument, ti would only go to 9.5 because arange excludes the end value.

edited Feb 02 '21 at 15:28

Pranav Hosangadi

answered Feb 02 '21 at 15:24

WVJoe

There are other issues with this: `step = 0.7 - 0.4; np.arange(0, 0.9, step)` – Andras Deak -- Слава Україні Feb 02 '21 at 17:09
Yes, it is not a perfect method. There is also `np.linspace(start,end,n_steps)`. This will give you both the start and end value and give you a vector with `n_steps` elements. – WVJoe Feb 02 '21 at 17:19

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