1
o=[]
o1=[1,2,3]
o.append(o1)
o1.append(9)
o.append(o1)
print(o)

for the above code I've been getting the output [[1, 2, 3, 9], [1, 2, 3, 9]] but i want to get the output as [[1, 2, 3], [1, 2, 3, 9]]. So what do i do ?

Mario Play
  • 11
  • 1

2 Answers2

1

Your code

o=[]
o1=[1,2,3]
o.append(o1)
o1.append(9)
o.append(o1)
print(o)

creates o holding your o1 list twice (if you want to check it yourself, print id(o[0]) and id(o[1]) and compare them), you need to append copies i.e. do:

import copy
o=[]
o1=[1,2,3]
o.append(copy.deepcopy(o1))
o1.append(9)
o.append(copy.deepcopy(o1))
print(o)

output:

[[1, 2, 3], [1, 2, 3, 9]]
Daweo
  • 21,690
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-1

you can try this :

o=[]
o1=[1,2,3]
o.append(o1)
o2 = [1,2,3,9]
o.append(o2)
print(o)

This is what I get in Jupyter Notebook :

enter image description here

akari
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