how to remove rows before a selected row

Question

I have a flat file data.txt in Linux/Centos server which contains a list of files e.g.

# cat data.txt
/home/user/data/1
/home/user/data/2
/home/user/data/3
/home/user/data/4
/home/user/data/5
/home/user/data/6

how can I remove from data.txt all rows before

/home/user/data/4

to receive this result

# cat data.txt
/home/user/data/4
/home/user/data/5
/home/user/data/6

`grep -A10000000000000000 /home/user/data/4 data.txt` – Ted Lyngmo Jan 16 '21 at 08:41 — Ted Lyngmo, Jan 16 '21 at 08:41

score 2 · Accepted Answer · answered Jan 16 '21 at 08:43

2

sed -ne '/^\/home\/user\/data\/4$/,//p'

answered Jan 16 '21 at 08:43

Martin Väth

This is better than my idea because it works on files with arbitrary lengths. – Ted Lyngmo Jan 16 '21 at 08:46
1

An alternative syntax: `sed -e '\|^/home/user/data/4$|,$!d'` – Cyrus Jan 16 '21 at 08:49

1 Answers1