loop exception handling. after deleting, go to the next iteration of the loop

Question

There is the following code:

def for_list(list_numbers):
    for n in list_numbers:
        try:
               ....
        except ...:
            list_numbers.remove(n)
               ....

Question: when hitting an exception, the element must be deleted, then the next element of the list must be accessed. How to do it?

you need to update your for loop to run on copy of list as `for n in list(list_numbers)` to handle updates in the length of list while removing element. Rest your `list_numbers.remove(n)` will work as intended — Moinuddin Quadri, Jan 14 '21 at 20:40

score 0 · Answer 1 · edited Jan 15 '21 at 08:54

0

Try:

for n in list(list_numbers):

edited Jan 15 '21 at 08:54

betontalpfa

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answered Jan 14 '21 at 20:39

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loop exception handling. after deleting, go to the next iteration of the loop

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