Is A::B::B::B::B...B::f() right ? Why could i do that?

Question

I don't know how to explain this:

namespace A
{
struct B
{
  static void  f()
  {
  }
};
}

int  main()
{
  A::B::B::B::B::B::B::B::B::B::B::f();
}

Why could i do :

A::B::B::B::B::B::B::B::B::B::B::f();

I don't understand it why it's happening.

Probably want the `language-lawyer` tag. Looks like you've found a C++ easter egg. — Eljay, Dec 18 '20 at 13:48
another dupe: https://stackoverflow.com/questions/65077931/why-does-this-use-of-using-declaration-compile — 463035818_is_not_a_number, Dec 18 '20 at 13:55
hard to find such dupes, I was only able to find it because I remembered it had something to do with batman :) — 463035818_is_not_a_number, Dec 18 '20 at 13:57
@largest_prime_is_463035818, I preferred that form of the question ;) — Mansoor, Dec 18 '20 at 13:58

score 9 · Accepted Answer · answered Dec 18 '20 at 13:55

9

inside class B, B refers to class B, as B::B.

so A::B::B refers to class B. and so on.

answered Dec 18 '20 at 13:55

Jarod42

1 Answers1