How to take in the elements of a list of unknown length as parameters for function? Python

Question

I would like to be able to take a list of unknown length in for function parameters like this:

With a list lis = [1, 2, 3, ...] and a function def func(a, b, c, ...): ... the elements of the list go into the function as individual parameters, func(1, 2, 3, ...) *not func([1, 2, 3, ...])

Is this possible?

Why would you want to do that, what is your function going to do? — ombk, Nov 24 '20 at 00:42
I have an object that takes in a function and parameters for the function as a list, so I don't know how many parameters there are going to be. — CrippledSquid89, Nov 24 '20 at 00:45

score 5 · Accepted Answer · answered Nov 24 '20 at 00:43

5

You can use * to connote many:

def func(*a):
    for value in a:
        print(value)

func(1,2,3)

func(1,2,3,4,5)

To input many items into this function from a list:

my_list = [i for i in range(20)]
func(*my_list)

answered Nov 24 '20 at 00:43

Yaakov Bressler

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ppwater · Answer 2 · 2020-11-24T00:52:59.713

1

The *args will give you all function parameters as a tuple:

def func(*a):
    a = list(a)
    print(a)

func(1,2,3)
func(1,2,3,4,5,6,7,8,9,10)

Or you can use it like this:

mylist = [i for i in range(10)]
func(*mylist)

edited Nov 24 '20 at 00:52

answered Nov 24 '20 at 00:46

ppwater

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How to take in the elements of a list of unknown length as parameters for function? Python

2 Answers2