Locate element without any name or class using Selenium and Python

Question

I'm using Selenium and I want to grab the 'a' tag so I can navigate into my user profile. What is the best way to do this?

Here is the HTML:

<div class="parent-cont">
  <div class="akd3 dafk4 dfan4">...</div>
  <div class="avndkd dakdf">...</div>
  <div class="fjkad fdadj dfakees">
    <a aria-label="tag" class="oa2 g5iad jhuo" href="/profile.php?id=1792" role="link" tabindex="0">
      <div class="dsks dssks">...</div>
      <div class="dka dk2 fdakdd">...</div>
    </a>
  </div>
</div>

score 0 · Answer 1 · answered Nov 22 '20 at 22:46

To locate the element you can use either of the following Locator Strategies:

Using css_selector:

element = driver.find_element_by_css_selector("a[aria-label='tag'][href='/profile.php?id=1792']")

Using xpath:

element = driver.find_element_by_xpath("//a[@aria-label='tag' and @href='/profile.php?id=1792']")

Ideally, to locate the element you need to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

Using CSS_SELECTOR:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "a[aria-label='tag'][href='/profile.php?id=1792']")))

Using XPATH:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//a[@aria-label='tag' and @href='/profile.php?id=1792']")))

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Locate element without any name or class using Selenium and Python

1 Answers1