Testing equality of arrays in C#

Question

I have two arrays. For example:

int[] Array1 = new[] {1, 2, 3, 4, 5, 6, 7, 8, 9};
int[] Array2 = new[] {9, 1, 4, 5, 2, 3, 6, 7, 8};

What is the best way to determine if they have the same elements?

Answer 1

You could also use SequenceEqual, provided the IEnumerable objects are sorted first.

int[] a1 = new[] { 1, 2, 3, 4, 5, 6, 7, 8, 9 };    
int[] a2 = new[] { 9, 1, 4, 5, 2, 3, 6, 7, 8 };    

bool equals = a1.OrderBy(a => a).SequenceEqual(a2.OrderBy(a => a));

Answer 2

By using LINQ you can implement it expressively and performant:

var q = from a in ar1
        join b in ar2 on a equals b
        select a;

bool equals = ar1.Length == ar2.Length && q.Count() == ar1.Length;

Answer 3

Will the values always be unique? If so, how about (after checking equal length):

var set = new HashSet<int>(array1);
bool allThere = array2.All(set.Contains);

Answer 4

var shared = arr1.Intersect(arr2);
bool equals = arr1.Length == arr2.Length && shared.Count() == arr1.Length;

Answer 5

Use extension methods (which are new in 3.0). If the length of the Intersection of the two arrays equals that of their Union then the arrays are equal.

bool equals = arrayA.Intersect(arrayB).Count() == arrayA.Union(arrayB).Count()

Succinct.

Answer 6

For the most efficient approach (Reflectored from Microsoft code), see Stack Overflow question Comparing two collections for equality irrespective of the order of items in them.

Answer 7

Framework 4.0 introduced IStructuralEquatable interface which helps to compare types such as arrays or tuples:

 class Program
    {
        static void Main()
        {
            int[] array1 = { 1, 2, 3 };
            int[] array2 = { 1, 2, 3 };
            IStructuralEquatable structuralEquator = array1;
            Console.WriteLine(array1.Equals(array2));                                  // False
            Console.WriteLine(structuralEquator.Equals(array2, EqualityComparer<int>.Default));  // True

            // string arrays
            string[] a1 = "a b c d e f g".Split();
            string[] a2 = "A B C D E F G".Split();
            IStructuralEquatable structuralEquator1 = a1;
            bool areEqual = structuralEquator1.Equals(a2, StringComparer.InvariantCultureIgnoreCase);

            Console.WriteLine("Arrays of strings are equal:"+  areEqual);

            //tuples
            var firstTuple = Tuple.Create(1, "aaaaa");
            var secondTuple = Tuple.Create(1, "AAAAA");
            IStructuralEquatable structuralEquator2 = firstTuple;
            bool areTuplesEqual = structuralEquator2.Equals(secondTuple, StringComparer.InvariantCultureIgnoreCase);

            Console.WriteLine("Are tuples equal:" + areTuplesEqual);
            IStructuralComparable sc1 = firstTuple;
            int comparisonResult = sc1.CompareTo(secondTuple, StringComparer.InvariantCultureIgnoreCase);
            Console.WriteLine("Tuples comarison result:" + comparisonResult);//0
        }
    } 

Answer 8

This will check that each array contains the same values in order.

int[] ar1 = { 1, 1, 5, 2, 4, 6, 4 };
int[] ar2 = { 1, 1, 5, 2, 4, 6, 4 };

var query = ar1.Where((b, i) => b == ar2[i]);

Assert.AreEqual(ar1.Length, query.Count());

Answer 9

I have found the solution detailed here to be a very clean way, though a bit verbose for some people.

The best thing is that it works for other IEnumerables as well.

Answer 10

    public static bool ValueEquals(Array array1, Array array2)
    {
        if( array1 == null && array2 == null )
        {
            return true;
        }

        if( (array1 == null) || (array2 == null) )
        {
            return false;
        }

        if( array1.Length != array2.Length )
        {
            return false;
        }
        if( array1.Equals(array2))
        {
           return true;
        }
        else
        {
            for (int Index = 0; Index < array1.Length; Index++)
            {
                if( !Equals(array1.GetValue(Index), array2.GetValue(Index)) )
                {
                    return false;
                }
            }
        }
        return true;
    }

Answer 11

There are, of course, many ways to compare arrays based on the structure. To add more to the answers above, you can write your own custom comparers. Let's say you want to check whether both, the 2 arrays, contain even elements - you define your comparison based on the business rules of your application, that's why it's so subjective.

Here is a way to do it, writing your own comparer. Please note that there is no much care about the GetHashCode() method and you have to write your custom equality logic, at this moment, based on the default behavior (compare reference types) .equals() will give you different results if you use another collection to hold the arrays and we are saying that these 2 arrays contain even numbers and they are therefore equal, but we are breaking the rule that "If two values x and y evaluate equal then they MUST have the same hashcode". Don't worry too much here because we are comparing integers. With that said here is the example:

using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApp5
{
    class EvenComparer : EqualityComparer<int>
    {


        public override bool Equals(int x, int y)
        {
            if((x % 2 == 0 && y % 2 == 0))
            {
                return true;
            }

            return false;

        }

        public override int GetHashCode(int obj)
        {
            return obj.GetHashCode();
        }
    }


    class Program
    {
        static void Main(string[] args)
        {

            //If you want to check whether the arrays are equal in the sense of containing the same elements in the same order

            int[] Array1 =  { 2, 4, 6};
            int[] Array2 =  {8, 10, 12 };



            string[] arr1 = { "Jar Jar Binks", "Kill! Kill!", "Aaaaargh!" };
            string[] arr2 = { "Jar Jar Binks", "Kill! Kill!", "Aaaaargh!" };

            bool areEqual = (arr1 as IStructuralEquatable).Equals(arr2, StringComparer.Ordinal);
            bool areEqual2 = (Array1 as IStructuralEquatable).Equals(Array2, new EvenComparer());

            Console.WriteLine(areEqual);
            Console.WriteLine(areEqual2);


            Console.WriteLine(Array1.GetHashCode());
            Console.WriteLine(Array2.GetHashCode());

        }
    }
}

After reading the answers I realize that nobody specified that you have to include the

   using System.Collections;

namespace or you will get a missing using directive or assembly reference error for using the IStructuralEquatable interface.

Hope it helps someone someday