How do I access an element from an integer like a list?

Question

I try to run the code:

for c in range(10, 21):
    print(c)
    print([c[1]])

And I get the error: TypeError: 'int' object is not callable Why? How can I pick a specific element from an integer?

Are you trying to get the 1st digit from an integer? Eg if `c = 10`, you want `c[1] = 0`? — Loocid, Nov 20 '20 at 00:52
`int` objects are not containers, they do not have any elements. Are you trying to get a specific digit from their digital representation? The easiest way would be to convert it to a string, so something like `int(str(c)[1])` — juanpa.arrivillaga, Nov 20 '20 at 01:01
Also, that *isn't* the error you get, you get "Int item is not subscriptable". — juanpa.arrivillaga, Nov 20 '20 at 01:02
Integers don't have digits. They don't have a base, either. Those are properties of *textual representations of* integers. — Karl Knechtel, Nov 20 '20 at 01:17

score 0 · Answer 1 · answered Nov 20 '20 at 01:03

0

result = [i for i in range(10,21)]
for c in result:
    print(c)
    print(result[1])

#what you are trying is illegal in python. Int 'int' object is not subscribable. #Only lists or tuples, set, string... are subscriptable.

answered Nov 20 '20 at 01:03

krishna

score -2 · Answer 2 · answered Nov 20 '20 at 00:56

-2

you are iterating in an iterable, you need to declare before the list to access to the element something like this:

a = range(10,21)
for i in a:
    print(i)
    print(a[1])

In your code every iteration the value of c are: 10 11 12 13 ... This is the reason of you error

answered Nov 20 '20 at 00:56

Sebastian Garzon

2 Answers2