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Referencing the help file for `Invoke-RestMethod:

PS /home/nicholas> 
PS /home/nicholas> $response = Invoke-RestMethod -Uri https://blogs.msdn.microsoft.com/powershell/feed/ 
PS /home/nicholas> 
PS /home/nicholas> $json = $response | ConvertTo-Json                                                   
WARNING: Resulting JSON is truncated as serialization has exceeded the set depth of 2.
PS /home/nicholas> 
PS /home/nicholas> $xml = $response | ConvertTo-Xml  
PS /home/nicholas> 
PS /home/nicholas> $xml.OuterXml

How can I convert the response to xml and output it, as above, in a single line?

Nicholas Saunders
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3 Answers3

2

The specific URI you're targeting returns XML content, which Invoke-RestMethod automatically parses into XML DOMs of type System.Xml.XmlElement (an array of such instances in this case).

A simple way to visualize the output is to access the .OuterXml property:

(Invoke-RestMethod -Uri https://blogs.msdn.microsoft.com/powershell/feed/).OuterXml

If you really need a single-line representation:

(Invoke-RestMethod -Uri https://blogs.msdn.microsoft.com/powershell/feed/).OuterXml -replace '\r?\n'
mklement0
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0

Just a slight variant:

PS /home/nicholas> 
PS /home/nicholas> $url="https://blogs.msdn.microsoft.com/powershell/feed/"                            
PS /home/nicholas> 
PS /home/nicholas> Invoke-RestMethod -Method Post -Uri $url -Body $body -ContentType 'application/xml'

which, despite a specified "ContentType" certainly seems to not be XML at least as printed to the console. Still, interesting.

Nicholas Saunders
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0

[xml]$testResult = (Invoke-RestMethod -Uri 'url').OuterXml $testResult.Details.Status

In case xml is 3

user16647678
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