How to extract the DOI sub-string from a URL string? [python]

Question

I have a list of urls of the following format:

https://doi.org/10.1145/2883851.2883900

I want to extract the values after "doi.org".Here in the example my expected output is:

10.1145/2883851

I could do it on single url but to apply how get the values from a list of URLs.

if its the same website: `extracted = [string.replace("https://doi.org/", "") for string in lst]` — Ironkey, Oct 07 '20 at 18:32
also possible duplicate? https://stackoverflow.com/questions/12023430/regex-url-path-from-url — Ironkey, Oct 07 '20 at 18:38
If you could do it to a single URL, doing it for all URLs in a list is a simple matter of iterating over the list. It looks like you might find a python tutorial helpful. There are many good ones online. Here's a good one: https://www.learnpython.org/en/Loops — Pranav Hosangadi, Oct 07 '20 at 18:39

score 2 · Accepted Answer · edited Oct 07 '20 at 18:41

2

If you have a list of urls with the same domain name and want to return a list of values in 10.1145/2883851 format :

def replace_url(urls):
    result = []
    for url in urls:
        result.append(url[16:]) # len of "https://doi.org/" is 16
    return result

edited Oct 07 '20 at 18:41

Pranav Hosangadi

answered Oct 07 '20 at 18:36

tbw3

1 Answers1