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This has been solved thank you very much

DynasticINF
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  • Does this answer your question? [fgets instructions gets skipped.Why?](https://stackoverflow.com/questions/2907062/fgets-instructions-gets-skipped-why) – Random Davis Sep 28 '20 at 17:47
  • Also if you stepped through your code line-by-line with a debugger, you'd clearly see nothing's getting "skipped". You should really have debugged this before posting here. – Random Davis Sep 28 '20 at 17:47
  • Always check the return value of fgets, scanf etc., and fail on any error. – pts Sep 28 '20 at 18:00
  • Never use `gets`! How is this comment relevant here? Because `scanf("%s")` has precisely the same problem. Never use `"%s"` in scanf. Always use `scanf("%14s")` (or the appropriate size). – William Pursell Sep 28 '20 at 18:07
  • `scanf("%s")` will stop when faced with space, `fgets` does not, it's not always correct to use `scanf`. – Uriya Harpeness Sep 28 '20 at 18:13

2 Answers2

1

Look here: https://stackoverflow.com/a/20156727/14273548

Copied answer to here because of miminum characters.

after this line scanf("%d",&e) add a getchar() like this :

scanf("%d",&e);
getchar();

when you press Enter the newline character stays in the buffer so when fgets is called the newline is passed to it and it actes as if you pressed Enter

Uriya Harpeness
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0

scanf() reads exactly what you asked it to, leaving the following \n from the end of that line in the buffer where fgets() will read it. I would recommend using fgets() for reading input too and using sscanf() to read choice integer:

    char input[10];

    ...
    fgets(input, 10, stdin);
    sscanf(input, "%d", &choice);
Rohan Kumar
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