Code giving error in switching letters out for eachother

Question

The code is glitching out when i'm trying to do a simple character exchange. The code is listed down below along with screen shots of the error.

#include <stdio.h>

int main()
{
    char Ghost[12] = "SimonGhost";
    int ghostdeathdate = 5;
    char Price;
    int Soap;
    while (ghostdeathdate > 0)
    {
        scanf("%c %d", &Price, &Soap);
        Ghost[Soap] = Price;
        printf("%s\n", Ghost);
        --ghostdeathdate;
    }
    return ghostdeathdate;
}

Don't post error message as images. Post it as text. – klutt Sep 28 '20 at 10:32 — klutt, Sep 28 '20 at 10:32

David Ranieri · Answer 1 · 2020-09-28T10:38:16.340

1

The problem is the new line left in the buffer in each call to scanf, you need to consume each new line with a space:

scanf("%c %d", &Price, &Soap);

should be

scanf(" %c %d", &Price, &Soap); // Notice a space before %c

edited Sep 28 '20 at 10:38

answered Sep 28 '20 at 10:34

David Ranieri

37,819
6
48
88

OK it works! TYSM Just to ask so the code needs a space in the inverted commas for it to work? – Seth Manuel Sep 28 '20 at 10:38
I have edited/added a link to relevant information. – David Ranieri Sep 28 '20 at 10:39
@SethManuel yes, the leading space consumes all blank spaces: `' '`, `'\t'` and `'\n'` – David Ranieri Sep 28 '20 at 10:55

Code giving error in switching letters out for eachother

1 Answers1