List resolver with tuples

Question

I have a list:

List = [('4022-a751',), ('0bfc-4d53',)]

And want to resolve it into the output below:

Output = ['4022-a751','0bfc-4d53']

Does this answer your question? [How to make a flat list out of list of lists?](https://stackoverflow.com/questions/952914/how-to-make-a-flat-list-out-of-list-of-lists) — Tomerikoo, Sep 16 '20 at 08:02

score 2 · Answer 1 · answered Sep 16 '20 at 07:50

2

list_ = [('4022-a751',), ('0bfc-4d53',)]
res = [x for item in list_ for x in item]

Output

['4022-a751', '0bfc-4d53']

answered Sep 16 '20 at 07:50

AlexisG

score 0 · Accepted Answer · answered Sep 16 '20 at 07:51

0

A tuple can be manipulated like an array with index.

input_arr = [('4022-a751',), ('0bfc-4d53',)]
output_arr = [a[0] for a in input_arr]

print(output_arr)

answered Sep 16 '20 at 07:51

yimingStar

score 0 · Answer 3 · answered Sep 16 '20 at 07:55

0

You can use this.

old_list= [('4022-a751',), ('0bfc-4d53',)]
new_list = [''.join(i) for i in old_list]
print(new_list)

answered Sep 16 '20 at 07:55

ron_olo

3 Answers3