Bash: -e option is gone from $@

Asked Sep 08 '20 at 17:19

Active Sep 08 '20 at 17:31

Viewed 37 times

I have a simple bash script:

#!/bin/bash
echo "$@"
echo $@
for i in "$@"; do
    echo $i
done

When I ran it with -e, the '-e' is gone.

[root@4e127766a19f /]# ./me.sh -G
-G
-G
-G
[root@4e127766a19f /]# ./me.sh -e

I've tried a few different switches like -f, -L, -l, -X, -x, etc. Only -e and -E did not echo themselves so far.

I've tested this on Debian and Centos, and guess that this might be expected. What is the reason? My Google search was not fruitful.

asked Sep 08 '20 at 17:19

Stephen

1

That's `echo` removing the `-e`, not bash itself. – Charles Duffy Sep 08 '20 at 17:27
1

Use `printf '%s\n' "$i"` instead of `echo $i` and you'll see it. – Charles Duffy Sep 08 '20 at 17:27
Also, see [Why is `printf` better than `echo`?](https://unix.stackexchange.com/questions/65803/why-is-printf-better-than-echo) on [unix.se]. – Charles Duffy Sep 08 '20 at 17:28
...and the APPLICATION USAGE and RATIONALE sections of the [POSIX `echo` standard](https://pubs.opengroup.org/onlinepubs/9699919799/utilities/echo.html) – Charles Duffy Sep 08 '20 at 17:28
I see, I missed that possibility! Thank you! – Stephen Sep 08 '20 at 17:34

0 Answers0