Index of repeating character in a string

Question

I am checking for single quotation (') and printing its index, output is always 0

S="'abc','dsd''eeee'"
for i in S:
    if(i=="'"):
        print(S.index (i))

how to get 0,4....?

Related: [How to find char in string and get all the indexes?](https://stackoverflow.com/q/11122291/4518341) — wjandrea, Aug 27 '20 at 22:58

score 1 · Accepted Answer · answered Aug 27 '20 at 22:48

1

str.index() only finds the first occurrence. Use enumerate instead.

for idx, i in enumerate(S):
    if i == "'":
        print(idx)

answered Aug 27 '20 at 22:48

wjandrea

1

`str.index` does find later occurrences if you ask it nicely. – superb rain Aug 27 '20 at 22:56
@superbrain yeah, but you'd need to know where to start from, which would require a state variable, which is annoying. – wjandrea Aug 27 '20 at 22:56

score 1 · Answer 2 · answered Aug 27 '20 at 23:02

1

You can use the re regular expression library for matching:

import re
pattern = r"'"
text = "'abc','dsd''eeee'"
indexes = [match.start() for match in re.finditer(pattern, text)]

answered Aug 27 '20 at 23:02

Josh

score 1 · Answer 3 · answered Aug 27 '20 at 23:14

1

Here is a one-liner using list comprehension -

S="'abc','dsd''eeee'"
[i[0] for i in enumerate(S) if i[1] == "'"]

[0, 4, 6, 10, 11, 16]

answered Aug 27 '20 at 23:14

Akshay Sehgal

3 Answers3