Returning from function and then coming back to same place (Python)

Question

I want to return variable from function using return and after that call same function, but resume from return. It this possible? Example:

def abc():
    return 5
    return 6
var = abc() # var = 5
###
var = abc() # var = 6

You cannot do this with `return` however, if you use `yield` you can do something liek this with a generator — juanpa.arrivillaga, Aug 24 '20 at 15:14

score 3 · Accepted Answer · answered Aug 24 '20 at 15:08

3

Generator example:

def abc():
    yield 5
    yield 6
gen = abc()
var = next(gen) # var = 5
###
var = next(gen) # var = 6

answered Aug 24 '20 at 15:08

Marat

13,099
2
37
44

score 2 · Answer 2 · answered Aug 24 '20 at 15:09

2

I think you're looking for a generator:

def abc():
    yield 5
    yield 6

gen = abc()
var = next(gen)
print(var)
var = next(gen)
print(var)

answered Aug 24 '20 at 15:09

user32882

4,174
4
28
56

score 0 · Answer 3 · answered Aug 24 '20 at 15:10

returning a value in python terminates the function's process. the whole point is that it is returning exactly one value, once being done. maybe try to solve your problem by returning a stack- with as many values as you need,

def abc():
    a = []
    a.append(6)
    a.append(5)
    return a
var = abc().pop # var = 5
###
var = abc().pop # var = 6

Returning from function and then coming back to same place (Python)

3 Answers3