How to print each element of a list of lists of variable length as a column in python?

Question

Consider the following list:

L = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

How can I achieve this printing pattern?

1 4 7
2 5 8
3 6 9

More specifically, how can I do it in general for any number of elements in L while assuming that all the nested lists in L have the same length?

Does this answer your question? [Transpose list of lists](https://stackoverflow.com/questions/6473679/transpose-list-of-lists) — roganjosh, Aug 21 '20 at 18:19

score 3 · Accepted Answer · edited Aug 21 '20 at 18:20

3

Try this:

L = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
for x in zip(*L):
    print(*x)

Output:

1 4 7
2 5 8
3 6 9

edited Aug 21 '20 at 18:20

wjandrea

answered Aug 21 '20 at 18:19

deadshot

user2415706 · Answer 2 · 2020-08-21T18:47:21.743

-1

L = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

    
for i in zip(*L):        
    print(*i)

Produces:

1 4 7
2 5 8
3 6 9

(*i) says to do all of the arguments inside of i, however many there are.

edited Aug 21 '20 at 18:47

answered Aug 21 '20 at 18:22

user2415706

1

That code doesn't produce that output. Maybe you forgot to `zip(*L)`, but that's already covered in [deadshot's answer](https://stackoverflow.com/a/63528156/4518341). – wjandrea Aug 21 '20 at 18:24
Yeah my bad, fixed. – user2415706 Aug 21 '20 at 18:48

2 Answers2