Bash: Formatting date

Question

I would like to use date in the following format: yyyyMM.dd.HHmm. i.e. 202008.15.1742

This is the Bash file:

#!/usr/bin/env bash
VERSION_CODE=$((($(date +%s%N)/1000000))
plutil -replace CFBundleVersion -string "$VERSION_CODE"

How do I set VERSION_CODE such that the current time appears in this format: yyyyMM.dd.HHmm?

#VERSION_CODE=$(date +%Y%m.%d.%H%M) #echo $VERSION_CODE 202008.13.2155 — GaryB, Aug 14 '20 at 00:55

score 5 · Answer 1 · answered Aug 14 '20 at 06:58

5

A pure Bash solution without spawning a sub-process:

printf -v VERSION_CODE '%(%Y%m.%d.%H%M)T'

answered Aug 14 '20 at 06:58

Léa Gris

score 2 · Accepted Answer · answered Aug 14 '20 at 00:52

2

You can do it like this:

VERSION_CODE=$(date +"%Y%m.%d.%H%M")

answered Aug 14 '20 at 00:52

1218985

2 Answers2