Skip exceptions in python

Question

I have a newbie questions: let say I have this list of stock in python

import requests

list = ["AMZN","APPL", "BAC"]

try:
    for x in list:
        url ='https://financialmodelingprep.com/api/v3/quote-short/'+x+'?apikey=demo'
        response = requests.request('GET', url)
        result = response.json()
        print(result[0]["price"]) 

except:
    pass

the second ticker will throw an exceptions, how do I make python to run the third ticker no matter what happen to the second ticker requests?

A blanket `except` is almost always a bug. See https://stackoverflow.com/questions/21553327/why-is-except-pass-a-bad-programming-practice — tripleee, Aug 13 '20 at 08:00

score 1 · Accepted Answer · answered Aug 13 '20 at 07:52

Use try-except inside for loop like below

import requests

list = ["AMZN","APPL", "BAC"]


for x in list:
    try:
        url ='https://financialmodelingprep.com/api/v3/quote-short/'+x+'?apikey=demo'
        response = requests.request('GET', url)
        result = response.json()
        print(result[0]["price"]) 

    except:
       pass

score 0 · Answer 2 · answered Aug 13 '20 at 07:52

You can use continue

import requests

list = ["AMZN","APPL", "BAC"]

for x in list:
    try:
        url ='https://financialmodelingprep.com/api/v3/quote-short/'+x+'?apikey=demo'
        response = requests.request('GET', url)
        result = response.json()
        print(result[0]["price"])
    except:
        continue

Skip exceptions in python

2 Answers2